Physics
Double Award
Double Award
Cambridge IGCSE
TOPIC 1A: FORCES and MOTION
Why is it that a steel block is heavier than a wood block? It obviously depends on how big the blocks are, but what about if the blocks are the same size?
The answer is that in a steel block, the particles are packed tightly together, so there is more matter in a small space. When we say 'matter', we mean solids, liquids or gases. For some substances, like gold, the particles themselves are more massive as well as being tightly packed. We say that gold is a very dense substance. There is a large quantity of mass in a small space.
Figure 1. Wood and stone blocks
These are approximately the same size -which one is heavier?
The blocks in figure 1 looks about the same size, but how would you check this? The correct term for the total 'size' of the block is the volume. For a regular shaped block like the wood, this is quite straight forward, but for the stone block there are special techniques, covered later in this section.
To compare any two substances, we need to have an identical volume to make it a fair test. Rather than cutting the blocks until they are the same volume, we can do some simple maths to compare them accurately. We can work out how massive they would be in a single unit of volume.
For example, if the mass of the wooden block is 400 g and has a volume of 100 cm3, then we can do a simple division and say that it has a mass of 4 g per 1 cm3. This is how density is measured, in units of grams per centimetre cubed (g/cm3). For much larger objects, we can switch to larger units and use kilograms per metre cubed (kg/m3), and this is the official international unit of density. However, a metre cubed is an enormous volume, so for most objects in a school lab, g/cm3 are commonly used.
Here is the formula for density:
| density (g/cm3) = | mass (g) |
| volume (cm3) |
| ρ = | m |
| V |
Notes:
Example:
The wooden block shown in Figure 1 has dimensions of 8cm x 10 cm x 25cm, and has a mass of 1.5 kg.
Calculate the density of the block.
Answer:
The volume of the block is 8 x 10 x 25 = 2000 cm3. If we want to use units of g/cm3 for density, we need to convert 1.5 kg into grams, which is 1500 g.
| ρ = | m | and therefore:- | ρ = | 1500 |
| V | 2000 |
So density ρ = 0.75 g/cm3.
You will need to know how to carry out a practical to find the density of an unknown substance. To do this, you will need to do the following:
| ρ = | m |
| V |
There are several standard ways to find the volume of a solid or liquid:
If the substance is a regular block with a rectangular cross section, then finding the volume is relatively easy:
For liquids, the volume can be found using a measuring cylinder. The volume of a liquid is typically measured in millilitres (ml), but a millilitre is the same volume as a cm3.
For irregular solids, for example a small stone, you will need a specialist piece of science apparatus called a eureka can, as shown in figure2:
Figure 2. Using a eureka can to find the volume of a stone
The can is filled with water until it leaks out of the spout at the side. Once the leaking has stopped, put an empty measuring cylinder under the spout and then place the stone in the can. The stone will displace water - effectively pushing it out of the way, and this displaced water can be collected in the measuring cylinder. The volume of the water collected is the same as the volume of the stone.
Questions:
1. A block of green plastic is shown here.
a) The formula is:
| ρ = | m |
| V |
b) The volume of the block is length x height x width,
V = 10 x 8 x 8 = 640 cm3
To find the density we use the formula from part (a), so:
| ρ = | 768 g |
| 640 cm3 |
2. The stone in figure 2 shown above in the eureka can has a mass of 71 g. Using measurements shown in the image, calculate the density of the stone.
The volume of water shown in the cylinder in figure 2 is 30 ml. (Each small division is 5 ml).
We know that
30 ml = 30 cm3 volume. The mass of the stone is given as 71 g. Therefore:
| ρ = | m |
| V |
| ρ = | 71 |
| 30 |
3. A customer orders are large block of aluminium for an art project.
a) The volume of this large block will be:
V = 1.2 x 2 x 0.8
V = 1.92 m3
The density formula is:
| ρ = | m |
| V |
So m = ρ x V,
m = 2700 x 1.92
m= 5 184 kg, or 5 180 kg to 3 sig figs (5.18 tonnes!)
b) This is a trick question! The density of a substance does not depend on the dimensions of the object! The density of aluminium is still 2700 kg/m3. You could go through the maths and halve the volume, but remember to halve the mass as well. You will then get the same answer for the density.
The density of pure water is exactly 1.0 g/cm3. (if you are interested, this is not a coincidence - the gram was defined this way). The density does change slightly with temperature, as the water expands. However, for iGCSE we can assume that it is 1.0 g/cm3.
If you put an object like a piece of wood on the surface of a pure water lake, then:
Most metals and stones sink, so they must have a density above 1.0 g/cm3. What about the huge container ship shown in figure 3? How can it float if it is made of metal?
Figure 3. A vast container ship - still floating!
(NOAA - CC 2.0 licence)
The answer is that the boat is made of metal on the outside, but has huge empty spaces inside that contain just air with a very low density. This means that the average density of the boat is less than 1.0 g/cm3 and it will float!
A hot air balloon 'floats' in air, so therefore must have a density less than the surrounding air - caused by the hot air expanding and taking up a larger volume.
In figure 4, many different liquids of different densities have been combined. From the top of the image we have:
Figure 4. Liquids of different densities.
Kelvinsong, CC BY 3.0
Now test your understanding using these quick, 10 minute questions on this topic from Grade Gorilla:
